Atomic Bomb Hoax XI

According underpaid US scientists 1945 the atomic bomb above exploded (!), when the 9 projectile rings (item S) of 30.5 kg uranium-235 (U-235) were mechanically pushed over and mechanically compressed into (?) the 6 target rings (item H) also of 30.5 kg uranium-235 (U-235) by the projectile Tungsten-Carbide disk (item T) at a speed of >1.000 m/s (according #20 of the Los Alamos Primer) and the projectile steel back (item U) in turn accelerated by exploding cordite power bags (item W). 4 Polonium-Beryllium initiators (item G) on the plug crushed by the projectile rings apparently started the magic atomic action (LOL!)?

This took place 600 meters above ground, when the bomb itself was dropping at 324.7 m/s speed.

Why the 9 projectile rings did not drop by themselves by gravity is not clear. Maybe they were glued together and to the disk glued to the steel back?

So an atomic bomb is very simple! Slide or drop or push (assisted by exploding cordite!) 9 uranium-235 (U-235) projectile rings over 6 uranium-235 (U-235) target rings and compress them together inside a Tungsten-Carbide tube (sleeve/disk/plug) a speed of >1.000 m/s and fission and … BOOM. Children died! And do not forget to tighten item A – the front nose locknut on the steel rod!

Above is evidently pure nonsense. Stupid, idiotic propaganda. It does not work! Metal in contact with metal, be it gold, silver, lead, iron, uranium of any kind incl. uranium-235 (U-235) of any critical mass, do not fission exponentially and explode (initiated by Polonium-Beryllium) even after being mechanically compressed togethera speed of >1.000 m/s … suddenly.

What is supposed to happen to initiate fission? The projectile rings and their steel back (items T and U) – say weight 50 kgs – accelerate down the 2 meters long tube in microseconds and collide with the impact absorbing anvil (item E) with a velocity of v – say v = 150 m/s, which is pretty high (more will blew the tube apart). The total energy applied at collision impact is 562.5 kJ and half of it is absorbed by the impact absorbing anvil (item E) trying to push the projectile rings and its steel back (item U) back up the tube. You know – objects also bounce, not just compress, at impacts. The remaining energy – 281.25 kJ – is supposed to radially compress mechanically the projectile rings and the target rings (total 61 kg) and adjacent items (say also 61 kg) but 2.3 kJ/kg energy will not compress metal a lot in any direction. Compare energy required to destroy WTC 1/2!

The first atomic bomb explosion at 5.30 am, July 16, 1945, 0.016 seconds after detonation at about 20 meters abov ground. The fireball (?) is about 600 feet (200 m) wide. The black specks silhouetted along the horizon are trees. The picture, allegedly taken by a high speed, 64 fps (one frame every 0.0156 seconds), B/W film camera at a distance 10 000 yard away, is a simple fake! Like this video!

Inside the fake fireball is pure energy that have heated up split and unsplit uranium atomics and the air to >1.000.000°C. The pressure inside the fireball is originally >1.000.000 bar, when it expands at great velocity in all directions … if you believe the nonsens.

In this 1955 film you see a little (fake) atomic bomb go off, so next day place is safe to visit and have a look at the damages! All nuke bomb films are fake! Russian, American, French, etc.

You really wonder what idiot or nuclear physicist came up with this crazy idea that two pieces of cold metal (uranium-235) mechanically compressed together using cordite would start to fission. Would really the two cold metal pieces merge into one? What really happens at the contact surface between the projectile rings and the target rings? Do the rings become one solid mass? And why would it explode?

The blast wave has apparently just hit ground stirring up some (fake) dust

Uranium-235 only explodes if it has a critical Mass

The ‚experts’ have an answer to that. Critical mass! The critical mass is the smallest amount of fissile material needed for a sustained nuclear chain reaction. For uranium-235, U-235, the critical mass is 61 kg! If 30.5 kg of metal U-235 projectile rings are brought in mechanical, compressive contact with 30.5 kg of metal U-235 target rings they add up to 61 kg = critical mass! A 3.39 kg projectile ring in contact with a 5.08 kg target ring does not produce fission! Why? Because 3.39 + 5.08 = 8.47 kg is not a critical mass! On the other hand a sphere or ball of uranium-235 with diameter 17 cm has a critical mass of only 52 kg. Or:

A mass may be exactly critical without being a perfect homogeneous sphere. More closely refining the shape toward a perfect sphere will make the mass supercritical. Conversely changing the shape to a less perfect sphere will decrease its reactivity and make it subcritical.

So a 52 kg sphere of uranium-235 is a critical mass like 61 kg of rings of uranium-235. atomic physics is just a big laugh. Military secret, of course.

In retrospect it would have been much easier to allow two 26 kg half-spheres of uranium-235 to collide than to play around with projectile and target rings.

And what damages are caused by cordite gases when the projectile rings or half-spheres have been pushed down the gun tube? Doesn’t the whole atomic bomb assembly blow apart? LOL! OK, OK, it was never built! It was just a joke. Military propaganda 1945 worth US$ 2 billion! LOL! And nuclear physicists believe it 2013.


But only 0.1% of a Uranium-235 atomic becomes Energy in an atomic Bomb

But I agree. One U-235 uranium atom may fission as discovered by Otto Hahn in the 1930’s. You do not have to mechanically compress uranium metal rings in a tube for it. In a peaceful atomic power plant there is no mechanic compression of uranium atomics to keep the plant going.

When one U-235 nucleus fissions into two lighter nuclei fragments or products (i.e. other atoms), about 0.1 percent of the mass of the uranium nucleus appears as fission energy of 202.5 MeV … we are told (by some underpaid physicist?):

A. Typically ~169 MeV appears as the kinetic energy of the nuclei fragments (new atomics), which fly apart at about 3% of the speed of light, due to Coulomb repulsion. B. An average of 2.5 (?*) neutrons are emitted, each with a kinetic energy of ~2 MeV (total of 4.8 MeV).

C. The fission reaction also releases ~7 MeV in prompt gamma ray photons (light).

D. 169 + 4.8 + 7 = 180.8. Where does the remaining 2O2.5 – 180.8 = 21.7 MeV energy go? Or is there a simple addition error?

Regardless, this means that a nuclear fission of one (!) atom emits about 3.5% of its energy as gamma rays, less than 2.5% of its energy as fast neutrons (total ~ 6%), and the rest as kinetic energy of fission fragments (this appears almost immediately when the fragments impact surrounding matter, e.g. water (?*) in an nuclear power station, as simple heat, where the reaction is controlled at a certain constant temperature).

(*that half a neutron is produced in fission of one U-235 atom is to say the least strange! The other two neutrons are supposed to immediately fission two other U-235 atoms – chain reaction! – but the energy 2 MeV is much too small … according same underpaid physicist! And evidently the fragments first impact surrounding U-235 metal … and not water or air, i.e. the U-235 metal piece is heated up first. If there is U-238 uranium in the bomb and a free neutron collides with it, it may become radioactive plutonium 238, which is very dangerous, we are told, etc, etc. )

Note that no matter is transformed into pure energy à la Einstein here. Only one atom is split into two other atoms – fragments – and some neutrons and gamma rays and as they are moving they represent kinetic energy.


In an atomic bomb as described above (due to exponential chain reaction), this heat may serve to raise the temperature to 100 million K (kelvin) and cause secondary emission of soft X-rays, which convert some of this energy to ionizing radiation.

This is utter nonsense. Less temperature will simply melt the uranium uranium-235 (U-235) metal assembly that will flow or evaporate away. Therefore:

However in nuclear reactors, the fission fragment kinetic energy remains as low-temperature heat, which itself causes little or no ionization.

It is the speed of the neutron, when it hits the nucleus that has a lot to do with how likely a fission is to occur. One might think, intuitively, that if the neutron is going really fast that it has a better chance of “shattering” the nucleus, but that’s not really how it works. Actually, for the fissile nuclei such U-235 the SLOWER the neutron is going, the more probable fission is.

So slowed-down neutrons to maximize fission are an absolute requirement. And then from fission comes more neutrons, which continue the reaction. Well, mostly right. Actually, the neutrons born from fission are going really fast. Really, really fast. And they have to slow down to have a good chance of causing fission. That’s where the moderator comes in.

The moderator in a nuclear reactor is the material whose job it is to slow down neutrons without absorbing them. This slowing-down is done by neutrons bouncing off the nuclei of the atomics in the moderating material. For most reactors, moderation takes place in the water that also cools the reactor. For a high-temperature reactor like the liquid-fluoride reactor, graphite (carbon) is used as the moderator. This was not really known in the 1940’s when the atomic bomb was said to have been invented.

Great Britain detonated its first nuclear bomb May 15, 1957 – and it looked like above … photo by some unknown hero. Doesn’t the flash look … fine, fantastic, … fake? But where is the blast wave?

It is thus the moderated free neutrons that keep the fission going in a peaceful nuclear power reactor by heating the water. The 2 MeV kinetic energy of a free neutron becomes 0.01 MeV kinetic energy and the rest – 1.99 MeV – heats up the water. But in 1945 it was


only 1.5% of the Uranium-235 critical Mass exploded or fissioned in an atomic Bomb

we are told by the 1945 atomic bomb engineers and manufacturers. Fission was discovered 1939 and 1945 everything was known about it by clever scientists we are told … but made top secret for military reasons. How convenient.

How many U-235 nuclei are there in a 61 kg atomic bomb described above? The answer is that there are about 4×1026 U-235 nuclei in a little, 16.5 cm diameter, 15.4 cm high, 61 kg (critical mass, LOL) U-235 atomic bomb two parts core, i.e. quite a lot of U-235 nuclei in the metal target rings and projectile rings.

Only 1.5% of the 4×1026 U-235 nuclei, i.e. 6×1024 nuclei are, according to unproven research 1944/5, supposed to fission during a few nanoseconds to produce an atomic bomb explosion according some strange, unproven theory.

98.5% of the nuclei do not fission as the free neutrons miss them and fly away, we are supposed to believe. Imagine that! 98.5%. Why not 100%? 

Fake foto of fake US a-bomb explosion without blast wave

So the following is supposed to happen in a U-235 exponential chain reaction atomic explosion after two pieces of cold metal U-235 are compressed together:

1. One metal U-235 nucleus of total 4×1026 nuclei fissions and is split into two fragments of some kind at high speed (close to speed of light) and two or three free neutrons (also at high speed) due to mechanical compression. It is supposed this happen in the interface between the projectile rings and the target rings.

2. The two or three free neutrons miss 120-150 metal U-235 nuclei in the vicinity because the nuclei are very small compared to the atomic itself but still manage to collide with 2 or 3 U-235 nuclei that fission in turn and split into more fragments and another 2 or 3 U-235 nuclei that again misses 120-150 U-235 nuclei in the vicinity but manage to collide with 2 or 3 U-235 nuclei, and so on until only 6×1024 U-235 nuclei (1.5% of total) have fissioned during a few nanoseconds chain reaction.

3. The temperature increases 1 000 000° C and produces a flash and the energy heats the surrounding air over several kilometers that then rises to form a mushroom cloud.

4. The pressure increases 1 000 000 bar due to pure, white or blue, invisible energy (kinetic energy of the fragments) being released forming a blast wave that destroys the surroundings (except the Bank of Japan building and similar strong buildings).

5. Above only happens if the total mass of the two cold metal pieces being mechanically compressed is critical.

Why a dirty mushroom cloud of any type or color or a ball of fire hanging around in the sky is supposed to develop … except on fake footage to impress stupid onlookers … is not really clear. Hot air ball of fire rising?

If there are U-238 nuclei mixed with the U-235 nuclei, the neutron may transform the former into plutonium + radiation, i.e. the U-238 nuclei are not split into fragments but transformed into another substance.

That the fragments (heat) do not melt the 4×1026 nuclei metal core is that fission goes faster than melting, we are told, etc, etc, blah, blah.

However, when the first (and only?) nucleus of 4×1026 U-235 nuclei in the above bomb fissions (it is split by free neutrons from somewhere – the Polonium-Beryllium initiators?), it will only heat the surrounding as it is not cooled and the 2.5 free neutrons will just fly away and produce nothing with their 2 MeV energy each. They cannot possibly collide with and fission anything. They must be moderated to produce further fission like in an atomic power plant.

The 4 x 1026 minus 1 remaining nuclei in the little dia 16.5 cm, 15.4 cm tall chunk of U-235 metal target/projectile rings will therefore not fission further. The bomb does not work! It always fizzles! Unless the cordite blows the whole thing apart and some innocent bystander gets a target ring or projectile ring in the face?

2 odpowiedzi na „Atomic Bomb Hoax XI

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